The standard deviation of X, denoted SD(X), is given by

$SD(X)=\sqrt{Var(X)}$

Find SD(aX + b) if X has variance $\sigma^2$

standard deviation

variance

Answered by LanceJ 1 year ago

$$SD(aX+b)$$

$$=\sqrt{Var(aX+b)}$$

$$=\sqrt{Var(aX)}$$

$$=\sqrt{a^2Var(X)}$$

$$=\sqrt{a^2\sigma^2}$$

$$=a\sigma$$

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Asked: 1 year ago