I need to find a fast way to expand $(3x^2 + y)^5$

Expand $(3x

jeffp

Answered by Aaron 3 years ago

Use the binomial expansion,

$$(3x^2+y)^5 = \sum_{k=0}^5 \begin{pmatrix} 5 \\ k \end{pmatrix} (3x^2)^k y^{5-k}$$

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Asked: 3 years ago