In how many ways can 8 people be seated in a row if

(a) there are no restrictions on the seating
arrangement?

(b) persons A and B must sit next to each other?

(c) there are 4 men and 4 women and no 2 men
or 2 women can sit next to each other?

(d) there are 5 men and they must sit next to each
other?

(e) there are 4 married couples and each couple
must sit together?

In how

jeffp

Answered by Aaron 2 years ago

**part (a)**

$$8!=40320$$

**part (b)**
Persons A and B can occupy 7 different positions and can be ordered in 2! ways, the rest of the people can occupy 6! positions,

$$7 \cdot 2! \cdot 6! =10080$$

**part (c)**

We have to alternate men and women in this case, starting with either a man or a woman and so we multiply by 2 and can order the men 4! ways and the women 4! ways,

$$2 \cdot 4! \cdot 4! = 1152$$

**part (d)**

If 5 men must sit next to each other they can only occupy 4 different spaces, the men can be ordered in 5! ways, and the remaining women can be ordered in 3! ways,

$$4 \cdot 5! \cdot 3!=2880$$

**part (e)**

The married couples can be ordered in 4! ways and each couple can be ordered in 2! ways,

$$4!(2!)^4=384$$

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Asked: 2 years ago