The Roadnet Transport Company has expanded its shipping capacity

# The Roadnet Transport Company has expanded its shipping capacity

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The Roadnet Transport Company has expanded its shipping capacity by purchasing 90 trailer trucks from a competitor that went bankrupt. The company subsequently located 30 of the purchased trucks at each of its shipping warehouses in Charlotte, Memphis, and Louisville. The company makes shipments from each of these warehouses to terminals in St. Louis, Atlanta, and New York. Each truck is capable of making one shipment per week. The terminal managers have indicated their capacity of extra shipments. The manager at St. Louis can accommodate 40 additional trucks per week, the manager at Atlanta can accommodate 60 additional trucks, and the manager at New York can accommodate 50 additional trucks. The company makes the following profit per truckload shipment from each warehouse to each terminal. The profits differ as a result of differences in products shipped, shipping costs, and transport rates.

 Terminal Warehouse St. Louis Atlanta New York Charlotte $1,800$2,100 $1,600 Memphis 1,000 700 900 Louisville 1,400 800 2,200 The company wants to know how many trucks to assign to each route (i.e., warehouse to terminal) to maximize profit. 1. Formulate a linear programming model for this problem. 2. Solve the model by using the computer The Roadnet maddy ### 1 Answer Answered by 6 years ago 365.9k points #### Oh Snap! This Answer is Locked Thumbnail of first page Excerpt from file: Math Tutorial The Roadnet Transport Company has expanded its shipping capacity by purchasing 90 trailer trucks from a competitor that went bankrupt. The company subsequently located 30 of the purchased trucks at each of its shipping warehouses in Charlotte, Memphis, and Louisville. The company Filename: M1069.pdf Filesize: 311.4K Downloads: 10 Print Length: 2 Pages/Slides Words: 395 ### Your Answer Surround your text in *italics* or **bold**, to write a math equation use, for example, $x^2+2x+1=0\$ or $$\beta^2-1=0$$

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