Physics: Impulse

Physics: Impulse


Asked by 2 years ago
365.9k points

A 5 kg steel ball strikes a wall with a speed of 15 m/s at an angle of 30o with the normal to the wall.  It bounces off with the same speed and angle.  If the ball is in contact with the wall for 0.2 s, what is the magnitude of the average force exerted on the ball by the wall?

Physics: Impulse
JasonJones

1 Answer

Answered by 2 years ago
389.5k points

$ I=\int\limits_{t_1}^{t_2}dt $

also, when the force and mass are constant then:

$ I=F \Delta t=m \Delta v = \Delta p $

where

$ F $ = constant total net force applied

$ \Delta t $ = time interval over which the force is applied

$ m $ = mass of the object

$ \Delta v $ = change in velocity produced by the force

given

$ M $ = 3 kg

$ v $ = 15 m/s

$ \theta $ = 30o

The y component of the momentum is not changed in this case.  The x component is changed by an amount:

$ \Delta P_x =-2Mv cos(\theta) $

and

$ F \Delta t = \Delta p \,\,\to\,\, F=\frac{\Delta p}{\Delta t} = \frac{-2Mv cos(\theta)}{\Delta t} = \frac{-2(5\,kg)(15\,m/s)cos(30^0)}{0.2\,s}=-649.5\,N $

$ ||F||=649.5 N $

Your Answer

Surround your text in *italics* or **bold**, to write a math equation use, for example, $x^2+2x+1=0$ or $$\beta^2-1=0$$

Use LaTeX to type formulas and markdown to format text. See example.

Sign up or Log in

  • Answer the question above my logging into the following networks
Sign in
Sign in
Sign in

Post as a guest

  • Your email will not be shared or posted anywhere on our site
  •  

Stats
Views: 7
Asked: 2 years ago

Related