EQUATION OF A STRAIGHT LINE (1)

EQUATION OF A STRAIGHT LINE (1)


C
Asked by 1 month ago
10 million points

Find the equation of the line with gradient $-\frac{2}{3}$, which passes through the point $(1,-4)$.

EQUATION OF
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1 Answer

C
Answered by 1 month ago
10 million points

[Think: the line has equation $y=-\frac{2}{3}x+c$, therefore it may be written $3y+2x=$constant.

Now since the line passes through $(1,-4)$, the constant may be found by substituting these corrdinates in the left-hand side.]

The equation of the line is

$3y+2x-12+2$

i.e $2x+3y+10=0$

$Note$: Check that the line (a) has gradient $-\frac{2}{3}$, (b) passes through $(1,-4)$

Your Answer

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Asked: 1 month ago

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