Solve $x^2-6x+13=0$, where $x\epsilon \mathbb{c}$

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chegendungu

$x^2-6x+13=0$

Using the formula

$x=\frac{+6\pm\sqrt{(36-4\times 1\times 13)}}{2}$

$=\frac{6\pm\sqrt{(-16)}}{2}$

$=\frac{6\pm4i}{2}$

$\therefore x=3\pm2i$.

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Asked: 2 months ago